TypeScript List<T>

Problem List<T> solves

Using the filter method of an Array<T> , in TypeScript, don't allow for additional parameters to be passed in and used as part of the filter condition. List<T> solves this problem by providing a where method. This where method do allow for additional parameters to be passed in and used as part of the filter. All standard Array<T> properties and methods are available on List<T>.

General Use

Define interface for <T>

interface Item { name: string };

Create List<T>

let list = new List<Item>();

Create and Add data to List<T>

let itemOne: Item = { name: "Name1" };
let itemTwo: Item = { name: "Name2" };
list.push(itemOne);
list.push(itemTwo);

Define filter (T, ...arg):boolean

let filter = (item: Item, name: string) => item.name === name;

Filter List<T> using where(filter, value)

let newList = list.where(filter, "Name1");

Development

Install Dev Dependencies

Below command only required for development.

npm install
npm run setup

Unit Tests

After running below gulp task a html codecoverage report is made available in directory ./analysis/coverage/lcov-report.

gulp test

Static Code Analysis

After running below gulp task two reports are made available in directory ./analysis/complexity. The HTML version is located in the report subdirectory.

gulp analyse

Note: complexity analysis is just experimental