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typelang

v1.0.0

Published

> A tiny language interpreter implemented purely in TypeScript's type-system

Downloads

3

Readme

🌳 TypeLang

A tiny language interpreter implemented purely in TypeScript's type-system

Introduction

This is an extremely simplified language interpreter implemented purely in TypeScript type annotations. You pass your code as a string and get back the result by hovering with your mouse on the resulting type annotation.

The syntax is Lisp-like. If you're not familiar with it, here's a quick comparison to JavaScript's syntax:

 LISP                      JavaScript

 (add 1 2)                 add(1, 2)
 (subtract 5 2)            subtract(5, 2)
 (add 3 (subtract 2 1))    add(3, subtract(2, 1))

You can pass multiple expressions and the last one is returned. For example:

 (add 1 2) (subtract 6 1) // 5, returns the result of 6 - 2

The language supports booleans, numbers, strings, conditionals (if statements), and calling the following built-in functions:

  • ++: Increases a number by one.
  • --: Decreases a number by one.
  • Eq: Checks if both of its arguments are equal.
  • And: Returns true if both of its arguments are true.
  • Or: Returns true if at least one of its arguments are true.
  • Join: Concatenates two strings together.

To declare a variable, use the Def keyword. This example initializes x to 3:

(Def x 3)

To define a function, use the Fun keyword. You pass the name of the function, the arguments that it takes, and finally, its body. The following example defines a function that adds a question mark (?) to its input:

(Def Ask (q) (Join q "?"))

Try running the code (See it live)

Install typelang with npm install typelang or with yarn install typelang (requires TypeScript v4.1.0 or above).

import { Eval } from "typelang";

// Empty
type Result = Eval<''>; // null

// Numbers
type Result = Eval<'123'>; // '123'

// Strings
type Result = Eval<'"hello"'>; // 'hello'

// Booleans
type Result = Eval<'True'>; // true
type Result = Eval<'False'>; // false

// Conditionals
type Result = Eval<'(If True "yes" "no")'>; // 'yes'
type Result = Eval<'(If False "yes" "no")'>; // 'no'
type Result = Eval<'(If 1 "truthy" "nope")'>; // 'truthy'

// Core functions:
// - Join (concat)
type Result = Eval<'(Join "hello" "world")'>; // 'helloworld'
type Result = Eval<'(Join "a" "b" "c" "d")'>; // 'abcd'
// - Equals
type Result = Eval<'(Eq 2 2)'>; // true
type Result = Eval<'(Eq "you" "me")'>; // false
// - Logical and
type Result = Eval<'(And True True)'>; // true
type Result = Eval<'(And False False)'>; // false
// - Logical or
type Result = Eval<'(Or True False)'>; // true
type Result = Eval<'(Or False True)'>; // true
// - Increase by one
type Result = Eval<'(++ 2)'>; // '3'
// - Decrease by one
type Result = Eval<'(-- 5)'>; // '4'

// Variables
type Result = Eval<'(Def x 1) x'>; // '1'
type Result = Eval<'undefined_variable'>; // null
type Result = Eval<'(Def x 2) (++ x)'>; // '3'
type Result = Eval<'(++ x) (Def x 2)'>; // '2'
type Result = Eval<'(Def x (++ 3)) (Def y (++ x)) (Join "result: " y)'>; // 'result: 5'

// Function declarations
// To declare a function: `(Fun FunctionName (arg1 arg2 ...) (FunctionBody))`
type Result = Eval<'(Fun Ask (q) (Join q "?")) (Ask "Here")'>; // 'Here?'
// - Variables declared inside a function can't be accessed from outside
type Result = Eval<'(Fun Add2 (n) (Def n 5)) n'>; // null
// - Functions scope can still access global variables
type Result = Eval<'(Def x "!") (Fun AddBang (i) (Join i x)) (AddBang "hey")'>; // 'hey!'
// - Functions scope can overshadow global scope
type Result = Eval<'(Def x 3) (Fun Add (x) (++ x)) (Add 1)'>; // '2'

// More examples scripts
type Result = Eval<'(Eq (++ 1) 1)'>; // false
type Result = Eval<'(Join (Join "foo" " " "bar") " " "baz")'>; // 'foo bar baz'
type Result = Eval<'(Def n 4) (++ (++ (++ n)))'>; // '7'
type Result = Eval<'(If (Eq "2" "3") "equals!" "not!")'>; // 'not!'
type Result = Eval<'(Or (Eq 3 1) (Eq 1 1))'>; // true
type Result = Eval<'(Def x "Hello") (If True (Join x " " "World!") "Bye!")'>; // 'Hello World!'
type Result = Eval<'(Def a 3) (Def b (++ a)) (++ b)'>; // '5'

// Invalid syntax
type Result = Eval<'(++ (++ '>; // never
type Result = Eval<') ++'>; // never
type Result = Eval<'"aa'>; // never

Note: TypeScript has a limitation on how deep its computation can get. Because of this, we're limited to small inputs. If you're getting the following error: Type instantiation is excessively deep and possibly infinite, please try using a smaller input.

Additional links