tsmixin
v1.0.0
Published
Simple mixin for TypeScript
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tsmixin
Simple mixin for TypeScript
install
npm i tsmixin
motivation
TypeScript Handbook entry on mixins describes an approach thal allows for mixins, but is a bit tedious to code: forces you to add class interface override, apply the mixins separately, and requires to add a helper function to your code base.
If you, like me, wanted it as simple as class X extends mixin(X, Y, Z) { ...
then this package might be of use.
Under the hood
The mixin()
or extmixin()
functions create and return anonymous class, with the mixin properties added.
Example #1: mixin()
E.g. mixin with no constructor/super call
import { mixin } from 'tsmixin';
class Callable {
constructor(public a: number) {}
call() {
console.log("Call!")
}
}
// Mixin class #2
abstract class Activable {
active: boolean;
activate() {
this.active = true;
console.log("Activating…");
}
deactive() {
this.active = false;
console.log("Deactivating…");
}
}
class MyClass extends mixin(Callable, Activable) { }
const my = new MyClass();
my.call();
my.activate();
Example #2: extmixin()
E.g. extend the first argument class and mix in the rest
import { extmixin } from 'tsmixin';
class Callable {
constructor(public aNumber: number) {}
call() {
console.log("Call!")
}
}
// Mixin class #2
abstract class Activable {
active: boolean;
activate() {
this.active = true;
console.log("Activating…");
}
deactive() {
this.active = false;
console.log("Deactivating…");
}
}
class MyClass extends extmixin(Callable, Activable) { }
const my = new MyClass(1); // notice that it will require the constructor arguments of Callable
my.call();
my.activate();
console.log(my.aNumber); // 1
Notes
- extmixin() can not use an abstract class as the extnded class, because of this intentional TypeScript limitation