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truncate-evenly

v1.0.3

Published

Truncate strings in an array to the maximum total length evenly.

Downloads

1,086

Readme

truncate-evenly: truncate strings in an array to the maximum total length evenly

Truncates items (typically strings) in the array using a best-effort approach, to fit the sum length of the result to maxSumLength.

The function doesn't make an attempt to work as fast as possible (so better use it for relatively small arrays only). Instead, it optimizes the quality of the result and the simplicity of the approach.

  • The algorithm tries to minimize the number of truncations, keeping the items lengths balanced. In a nutshell, it first tries to shrink the longest item to the next one shorter, then do the same over and over until it reaches maxSumLength. See unit tests for details.
  • If appendEllipsis is passed, it will be called on the truncated elements to append the "ellipsis" marker. This marker won't count towards the sum length of the result though.
  • Works with any items that have length and slice properties (strings, sub-arrays, buffers or your custom objects).
  • You can also pass maxIterations to limit the number of the inner iteration. This acts as a circuit breaker in case of some unknown bug in the algorithm.

Examples

const entriesIn = ["123456789", "12", "1234567890123456789"];
const entriesOut = truncateEvenly(entriesIn, 12, (s) => s + "…");
expect(entriesOut).toMatchInlineSnapshot(`
  [
    "12345…",
    "12",
    "12345…",
  ]
`);

A good illustration on how the algorithm works step by step, getting closer and closer to the desired maximum length, is below:

expect(
  truncateTestHelper(12, {
    a: "1234567890123456789",
    b: "123456789",
    c: "12",
  })
).toMatchInlineSnapshot(`
  "0) a=1234567890123456789  b=123456789            c=12
   1) a=123456789            b=123456789            c=12
   2) a=12345                b=12345                c=12
   3) a=12345…               b=12345…               c=12 <-- RESULT"
`);