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times-iterator

v1.0.0

Published

This package is inspired by the syntax of the Ruby programming language. It adds an iterator that can be called 'n' times with a function that is passed to one of the methods of the iterator.

Downloads

67

Readme

times-iterator

This package is inspired by the syntax of the Ruby programming language and lets you iterate over a number of times and do something with it.

Installation

npm

npm install times-iterator

yarn

yarn add times-iterator

API

The argument that you pass to the times function must be greater than 0

do - this method always returns the instance of the "times" function, so you can chain it

  let n = 0
  // will be called 20 times
  times(20).do((number, index, exitFn) => n++)
  // n = 20

  let k = 0
  // will also be called 20 times
  times(10)
     .do((number, index, exitFn) => k++)
     .do((number, index, exitFn) => k++)
  // k = 20

map

  const arr = times(10).map((number, index, arr, exitFn) => number * 2)
  // arr = [2, 4, 6, 8, 10, 12, 14, 16, 18, 20]

reduce

  const sum = times(10).reduce((acc, number, index, exitFn) => acc + number, 0)
  // sum = 55

filter or select

  const arr = times(10).filter((number, index, arr, exitFn) => number % 2 === 0)
  // arr = [2, 4, 6, 8, 10]

  const anotherArr = times(10).select((number, index, arr, exitFn) => number % 2 === 0)
  // anotherArr = [2, 4, 6, 8, 10]

takeWhile - takes while the condition is true

  const arr = times(10).takeWhile((number, index, arr, exitFn) => number < 5)
  // arr = [1, 2, 3, 4]

takeUntil - takes till the condition becomes true

  const arr = times(10).takeUntil((number, index, arr, exitFn) => number === 5)
  // arr = [1, 2, 3, 4]

Reverse

Every method has a reverse version, for example: reverseDo, reverseMap, reverseReduce, reverseFilter, reverseSelect, reverseTakeWhile, reverseTakeUntil

  let n = 0
  // will be called 20 times
  times(20).reverseDo((number, index, exitFn) => n++)
  // n = 20

  let k = 0
  // will also be called 20 times
  times(10)
     .reverseDo((number, index, exitFn) => k++)
     .reverseDo((number, index, exitFn) => k++)
  // k = 20

You can also go reverse by passing a second argument as true to any function you use

  let n = 0
  // will be called 20 times
  times(20).do((number, index, exitFn) => n++, true)
  // n = 20
    
  let k = 0
  // will also be called 20 times
  times(10)
    .do((number, index, exitFn) => k++, true)
    .do((number, index, exitFn) => k++, true)
    // k = 20

Exit

You can exit the loop by calling the exit function

  let n = 0
  // will be called 20 times
  times(20).do((number, index, exit) => {
    n++
    if (n === 10) exit()
  })
  // n = 10

It gives you the possibility to create infinite loops since you can pass Infinity as the first argument

  let n = 0
  times(Infinity).do((number, index, exit) => {
    n++
    if (n === 10) exit()
  })
  // n = 10
Exit function is available in all the methods so you can quit the loop at any time you want!

Usage

import { times } from 'times-iterator'

const evenNumbersTill100 = times(100).select(number => number % 2 === 0)

React

import React from 'react'
import { times } from 'times-iterator'

const Dots = props => {
  return (
    <div class={'flex items-center space-x-10'}>
      {times(props.dotsNumber).map(n => <div key={n} className={'w-4 h-4 rounded-full'} />)}
    </div>
  )
}