react-pagex
v1.2.1
Published
The `react-pagex` is a very tiny library for manage react app routes. It's very simple to use.
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React PageX
The react-pagex
is a very tiny library for manage react app routes. It's very simple to use.
Availabel Hooks and Components
import {
Link,
useRoute,
useGroup,
useQuery,
Navigate,
Route,
Routes,
Parser
} from 'react-pagex'
Useg
import {Link, Routes, Route} from 'react-pagex'
const Home = ({params, query}) => {
return <h1>Home</h1>
}
const About = ({params, query}) => {
return <h1>About</h1>
}
const Contact = ({params, query}) => {
return <h1>Contact</h1>
}
export default () => {
return (
<Routes
onError={() => {
}}
>
<ul>
<li><Link label="Home" path="/" /></li>
<li><Link label="Service" path="/service" /></li>
<li><Link label="Contact" path="/contact" /></li>
<li><Link label="Unknown" path="/wrong-path" /></li>
</ul>
<Route path='/' render={Home} />
<Route path='/about' render={About} />
<Route path='/service' render={Service} />
<Route path='/contact' render={Contact} />
</Routes>
)
}
Link Component
const LinkComp = ({children, ...props}) => <div>{children}</div>
<Link
label="Home"
href="/"
noHref={true}
component={LinkComp}
/>
// With Children
<Link
href="/"
noHref={true}
component={LinkComp}
>Children</Link>
Routes Component
Routes
used the useGroup hook
<Routes
basepath=""
onError={() => {
}}
onFound={(route) => {
}}
>
children
</Routes>
Route Component
Route
used the useRoute hook
<Route
path="posts/:id"
render={Render}
/>
Navigate
Navigate Page without Link
Component
import {Navigate} from 'react-pagex'
Navigate.go('/path')
Navigate.back()
Navigate.forward()
Navigate.reload()
useGroup
const App = () => {
useGroup({
basepath: '',
onError: () => {},
onFound: () => {},
})
return <>app</>
}
useRoute
const App = () => {
const params = useRoute('/path')
if(params){
return <div>Route Match</div>
}
return <></>
}
useQuery
Just get the current route query with an object
Parser
The Parser
is a module for match and parse the route
const params = Parser.isMatch('/path/:id', 'compare path')