ngx-if-platform
v3.1.0
Published
Angular directive for repeating HTML element by count
Downloads
77
Readme
Angular directive for conditional display based on platform
✓ Angular 19 compatible
Here's the demo or stackblitz live preview or codesandbox live preview
- Lightweight
- No dependencies!
- Directive way
🛠️ Install
- Use yarn (or npm) to install the package
yarn add ngx-if-platform
- Add
NgxIfPlatformModule
(or specific directive) into yourimports
import { NgxIfPlatformModule } from 'ngx-if-platform';
@Component({
standalone: true,
imports: [NgxIfPlatformModule /* , ... */],
// ...
})
or
import { NgxIfPlatformModule } from 'ngx-if-platform';
@NgModule({
// ...
imports: [
// ...
NgxIfPlatformModule
]
})
🚀 Quick start
Example code
<!-- ngxIf -->
<div *ngxIfBrowser>Is browser</div>
<!-- ngxIf can be disabled -->
<ng-template [ngxIfServer]="true">Is server (disabled)</ng-template>
<!-- ngxIf else statement -->
<ng-template [ngxIfServer] [ngxIfNotServer]="notServer">Is server</ng-template>
<ng-template #notServer>Not server</ng-template>
Result
Is browser
Is server (disabled)
Not server
🛠️ Options
There are these directives: ngxIfBrowser, ngxIfServer, ngxIfWorkerApp, ngxIfWorkerUi
Directive & attributes
| Option | Type | Default | Description | | --------------------- | ----------- | ------- | ------------------------------------------ | | [ngxIfBrowser] | boolean | true | Directive can be disabled | | [ngxIfNotBrowser] | templateRef | none | TemplateRef used if confition do not match | | [ngxIfServer] | boolean | true | Directive can be disabled | | [ngxIfNotServer] | templateRef | none | TemplateRef used if confition do not match |
🔧 Compatibility
| Angular | ngx-if-platform | Install |
| --------- | --------------- | ---------------------------- |
| >= 18 | 3.x | yarn add ngx-if-platform
|
| >= 14 | 2.x | yarn add ngx-if-platform@2
|
| >= 12 | 1.x | yarn add ngx-if-platform@1
|
| >= 5 < 13 | 0.x | yarn add ngx-if-platform@0
|
🪪 License
Copyright © 2021 - 2024 Dominik Hladik
All contents are licensed under the MIT license.