nested-objects-util
v1.1.2
Published
A module to filter and diff complex nested objects having circular references.
Downloads
683
Maintainers
Readme
nested-objects-util
A minimalist inspection module to filter and diff complex nested objects having circular references.
It was implemented to filter out some values from inconveniently nested objects with circular references and then diff them.
It's designed to work both on nodejs and browser without any dependencies or additional polyfills.
Performance is currently not the key feature of this module, so please use more optimised libraries for e.g. deep equal.
Installation
npm install --save nested-objects-util
yarn add nested-objects-util
Or just copy index.min.js
into the console and start using NestedObjectsUtil
object.
Usage
const nestedObjectsUtil = require('nested-objects-util')
nestedObjectsUtil.flatten(object: object, sortKeysFlag = false): object
Flatten object by keys composed from own nested properties.
nestedObjectsUtil.flatten({
keyA: {
keyE: ['value3', 'value4'],
keyF: null,
keyD: 'value2',
keyB: {
keyC: 'value'
}
}
})
returns:
{
"keyA.keyE.0": "value3",
"keyA.keyE.1": "value4",
"keyA.keyF": null,
"keyA.keyD": "value2",
"keyA.keyB.keyC": "value"
}
with sortKeys=true it would return:
{
"keyA.keyB.keyC": "value",
"keyA.keyD": "value2",
"keyA.keyE.0": "value3",
"keyA.keyE.1": "value4",
"keyA.keyF": null
}
nestedObjectsUtil.unflatten(object: object): object
Unflatten object by keys composed from own nested properties.
nestedObjectsUtil.unflatten({
'keyA.keyB.keyC': 'value',
'keyA.keyD': 'value2'
})
returns:
{
"keyA": {
"keyB": {
"keyC": "value"
},
"keyD": "value2"
}
}
nestedObjectsUtil.accessProperty(keys: string|string[], parent = global window): any
Access object's nested property.
const nestedObject = {
keyA: {
keyB: {
keyC: 'value'
}
}
}
nestedObjectsUtil.accessProperty('keyA.keyB.keyC', nestedObject)
returns:
"value"
nestedObjectsUtil.discardCircular(object: object, stringifyFlag = false): object|string
Discard circular references (to avoid "Converting circular structure to JSON" error).
const a = {
b: 1
}
a.c = a
nestedObjectsUtil.discardCircular(a)
returns:
{
"b": 1,
"c": "~"
}
nestedObjectsUtil.filterValue(object: object, query: any|any[], flattenFlag = false): object
Filter a nested object by value or values (if array passed). Strict comparison is performed.
const a = {
b: {
c: 'str',
d: 'str2'
},
e: 'str',
f: {
g: {
h: 'str',
i: 'str3'
},
j: 'str4'
},
k: ['str', 'str5']
}
a.l = a.b
nestedObjectsUtil.filterValue(a, 'str')
returns:
{
"b": {
"c": "str"
},
"e": "str",
"f": {
"g": {
"h": "str"
}
},
"k": ["str"]
}
or with flattenFlag = true
nestedObjectsUtil.filterValue(a, 'str', true)
returns:
{
"b.c": "str",
"e": "str",
"f.g.h": "str",
"k.0": "str"
}
nestedObjectsUtil.downloadStringified(object: object, space = 2): string|undefined
On browser with HTML5 download API: stringify, format and download the object.
Else: return stringified text.
const a = {
b: 1,
c: {
d: 2,
e: 2
}
}
a.f = a
a.g = a.f
const obj = nestedObjectsUtil.discardCircular(a)
nestedObjectsUtil.downloadStringified(obj)
returns:
{
"b": 1,
"c": {
"d": 2,
"e": 2
},
"f": "~",
"g": "~"
}
nestedObjectsUtil.areObjectsEqual(objectA: object, objectB: object, skipProperties?: string[]): boolean
Compare two objects against each other after discarding circular references, flattening and ordering keys.
const objectA = {
keyA: {
keyB: {
keyC: 'value'
},
keyD: 'value2',
keyE: ['value3', 'value4']
}
}
objectA.circular = objectA
const objectB = {
keyA: {
keyE: ['value3', 'value4'],
keyD: 'value2',
keyB: {
keyC: 'value'
}
}
}
objectB.circular = objectB
nestedObjectsUtil.areObjectsEqual(objectA, objectB)
returns:
true
It is also possible to skip certain properties when comparing the objects by providing an array to string properties.
const objectA = {
keyA: {
keyB: {
keyC: 'value'
},
keyD: 'value2',
keyE: ['value3', 'value4']
}
}
objectA.circular = objectA
const objectB = {
keyA: {
keyB: {
keyC: 'DIFFERENT_VALUE'
},
keyD: 'value2',
keyE: ['value3', 'value4']
}
}
objectB.circular = objectB
nestedObjectsUtil.areObjectsEqual(objectA, objectB, ['keyA.keyB.keyC'])
returns:
true
nestedObjectsUtil.getObjectsDiff(objectA: object, objectB: object, sortKeysFlag = false, flattenFlag = false): object
Get the properties which differ between object A and object B and return only those from object B.
const objectA = {
keyA: {
keyB: {
keyC: 'value'
},
keyD: 'value2',
keyE: ['value3']
}
}
objectA.circular = objectA
const objectB = {
keyA: {
keyB: {
keyC: 'value'
},
keyD: 'value2_CHANGED',
keyE: ['value3_CHANGED']
}
}
objectB.circular = objectB
nestedObjectsUtil.getObjectsDiff(objectA, objectB)
returns:
{
"keyA": {
"keyD": "value2_CHANGED",
"keyE": ["value3_CHANGED"]
}
}
Example browser usage
In the browser, NestedObjectsUtil object is exposed either to window or with AMD.
Filter out 'abcd' value from the flattened object and download stringified JSON via HTML5 API with:
const object = NestedObjectsUtil.filterValue(App.SomeHugeObject, 'abcd', true)
NestedObjectsUtil.downloadStringified(object)
Discar circular references from the object, then flatten and download it.
let object = NestedObjectsUtil.discardCircular(App.SomeHugeObject)
object = NestedObjectsUtil.flatten(object)
NestedObjectsUtil.downloadStringified(object)
Test
npm run test
yarn test