lqueue

Create queue using linked list. Support forEach, enqueue,dequeue,clear,enqueue All, dequeueAll A Simple Queue using Linked Link Datastructure

When I was using javascript Array and calling array.shift() method to get first element and It was terrible if array contains more than 100,000 elements.

var start = new Date().getTime()
for(var i = 0; i< 100000; i++){
 array.shift();
}
var duration = new Date().getTime() - start;// duration is so large, greater than 3 minutes

I used Linked List to improve performance, and apply it for 1000,000 elements.

var start = new Date().getTime()
for(var i = 0; i< 1000000; i++){
 queue.dequeue();
}
var duration = new Date().getTime() - start;// duration  = 8 for 1000000 elements

Example: Queues using linked list. Visit here to test: https://tonicdev.com/5788a641565456130014d2c1/5788a641565456130014d2c2

var LQueue = require('linked-queue')
var queue = new LQueue()
queue.length === 0 //=> true
queue.enqueue(10)
queue.length  //=> 1
queue.first() ; // => 10
queue.last() ; // => 10
queue.enqueueAll([11,12]); // queues elements: 10,11,12
queue.fist(); //=> 10
queue.last();// => 12
queue.length;// => 3

queue.dequeue()// return 10, queus elements: 11,12
queue.forEach(function(data){
    console.log(data);
});
//=> print: 11 12
queue.dequeueAll(function(data){
    console.log(data);
});
//=> print: 11 12
queue.length //return 0
queue.isEmpty(); //return true;
queue.enqueueAll([1,2]);
queue.length;//return 2
queue.clear();
queue.length// return 0

API

queue = new LQueue()

queue.enqueue(value)

Push a value on the end.

queue.enqueueAll(array)

Push all values of array on the end of queue.

value = queue.dequeue()

Remove a value off the beginning.

queue.dequeueAll(callbackfn)

Remove all values off the beginning. Each dequeued data will be call by callbackFn(data)

queue.length

return size of queue.

value = deque.forEach(callbackfn)

Get all values of queues without removing. Each data will be call by callbackFn(data)

value = queue.last()

Examine the value of the end without removing it.

value = queue.first()

Examine the value of the beginning without removing it.

queue.clear()

Remove all entries.

About the Code

I was convinced by a blog posting