j5afe
v1.0.4
Published
Dependencies: <a href="https://github.com/acornjs/acorn">Acorn.js</a>
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J5afe Javascript Obfuscation/Deobfuscation Framework
Installation
npm i j5afe
Dependencies: Acorn.js
Acorn is used for the parser and BreakpointAST takes care of the recursive path.
example
var code = `
let lol = 10;
console.log(lol)
if (lol == 10 + 10) {
console.log("ok")
} else {
console.log("nop")
}
`
let br = new BreakPointAST(code)
br.addNodeBreakPoint("CallExpression", function(ctx, node) {
console.log(node)
})
br.addNodeBreakPoint("Literal", function(ctx,node) {
console.log(node.value)
})
br.addNodeBreakPoint("BinaryExpression", function(ctx, node) {
console.log(ctx.evaluate(node))
})
br.walk()
Obfuscation
You can create constant unfolding
let d = 10 * 20 + 30 >> 1333333333;
let dd = "lol"
become
let d = (10 + 1337) * (20 + 1337) + (30 + 1337) >> 1333333333 + 1337;
let dd = "lol";
with
br.addNodeBreakPoint("Literal", function(ctx, node, builder) {
if (typeof node.value !== 'number')
return
ctx.replaceExpression(node, builder.createBinaryExpression(
'+', builder.createLiteral(node.value), builder.createLiteral(1337)
)
)
})
let d = 10 * 10 + (1 ^ 2) + 2000 * 300 - (2 * 6);
let dd = "lol"
Become
let d = (function ok() {
return 10;
})() * (function ok() {
return 10;
})() + ((function ok() {
return 1;
})() ^ (function ok() {
return 2;
})()) + (function ok() {
return 2000;
})() * (function ok() {
return 300;
})() - (function ok() {
return 2;
})() * (function ok() {
return 6;
})();
let dd = "lol";
With
let br = new BreakPointAST(code)
br.addNodeBreakPoint("Literal", function(ctx, node, builder) {
if (typeof node.value !== 'number') return;
ctx.replaceExpression(
node,
builder.createCallExpression(
builder.createFunctionExpression(
id=builder.createIdentifier("ok"),
expression=false,
generator=false,
async=false,
params=[],
body=builder.createBlockStatement(
body=[
builder.createReturnStatement(
argument=builder.createLiteral(
node.value
)
)
]
)
)
)
)
})
br.walk()
MBA linear equation random
let d = (10 + 10) + 5 * 6 + 6 + 30 * 1337 - 10;
let dd = "lol"
Become
let d = -(- -(-10 + -10) + -(5 * 6)) - -6 - -(30 * 1337) + -10;
let dd = "lol";
With
let br = new BreakPointAST(code)
br.addNodeBreakPoint("BinaryExpression", function(ctx, node, builder, obfu) {
ctx.replaceExpression(node, obfu.generate_mba(node))
})
br.walk()
Deobfuscation
Constant folding
let d = (10 + 1337) * (20 + 1337) + (30 + 1337) >> 1333333333 + 1337;
let dd = "lol";
Become
let d = 111;
let dd = "lol";
with
br.addNodeBreakPoint("BinaryExpression", function(ctx, node, builder) {
ctx.replaceExpression(node, builder.createLiteral(ctx.evaluate(node)))
})
br.walk()