gulp-sloc4
v1.0.0
Published
A port of the grunt-sloc plugin for gulp
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gulp-sloc4
A port of the grunt-sloc plugin for gulp with some minor changes.
NOTE Taken from gulp-sloc4 and modified for Gulp 4.00.
Usage
First install the gulp-sloc4
plugin as a development dependency:
npm install --save-dev gulp-sloc4
Then, add it to your gulpfile.js
:
var sloc = require('gulp-sloc4');
gulp.task('sloc', function(){
gulp.src(['scripts/*.js'])
.pipe(sloc());
});
This would output the following:
[gulp] -------------------------------
[gulp] physical lines : 135
[gulp] lines of source code : 97
[gulp] total comment : 5
[gulp] singleline : 5
[gulp] multiline : 0
[gulp] empty : 33
[gulp]
[gulp] number of files read : 2
[gulp] strict mode
[gulp] -------------------------------
API
sloc(options)
options.tolerant
Type: Boolean
, Default: false
Set as false to analyze only files with a subset of popular extensions. true to analyze files with any file extension. The default is false.
If true, the SLOC will be executed on all of the files specified, regardless of file extension. With tolerant
set to false
, or unspecified, only supported file extensions will be analyzed.
options.reportType
Type: String
, Default: stdout
It will generate a JSON file with the SLOC analysis results and sends it further downstream. Use with the reportFile
option if you want to customize the file name. You may want to pipe to the gulp.dest()
method to write it out to specified folder. Example:
var sloc = require('gulp-sloc4');
gulp.task('sloc', function(){
gulp.src(['lib/**/*.js'])
.pipe(sloc({
reportType: 'json'
}))
.pipe(gulp.dest('./reports/'));
});
Would output the following in the file ./reports/sloc.json
:
{"total":138,"source":100,"comment":5,"single":5,"block":0,"empty":33,"file":2}
options.reportFile
Type: String
, Default: sloc.json
The name of the file which would contain you'd like to output the JSON file. Use with the json
as reportType
. Ignored if used with the stdout
report type. Example:
var sloc = require('gulp-sloc4');
gulp.task('sloc', function(){
gulp.src(['./test/**/*.js'])
.pipe(sloc({
reportType: 'json',
reportFile: 'testSloc.json'
}))
.pipe(gulp.dest('./reports/'));
});
Would output the sloc results in the file ./reports/testSloc.json
.
options.reportElements
Type: Object
, Default:
{
before: '-------------------------------',
after: '-------------------------------',
mode: true
}
Options used to customize output message. Use with the stdout
as reportType
. Ignored if used with the json
report type.
before
- Line printed before report. Set tofalse
to disable line before report.after
- Line printed after report. Set tofalse
to disable line after report.mode
- Print strict/tolerant mode information iftrue
.
options.metrics
Type: Array[String]
, Default: ['total', 'source', 'comment', 'single', 'block', 'mixed', 'empty', 'file']
Metrics that are returned in report.
Supported Languages and Extensions
- JavaScript -
js
- CoffeeScript -
coffee
orcoffeescript
- C / C++ -
c
orcc
- Python -
py
- Java -
java
- PHP -
php
FAQ
I'm getting a
TypeError: Cannot read property 'toString' of null;
.You probably have folders in your stream and
sloc
tries to read their contents. Change this:gulp.src(['src/**']).pipe(sloc())
To this:
gulp.src(['src/**'], {nodir: true}).pipe(sloc())
Contributing
- Fork it
- Create your feature branch (
git checkout -b my-new-feature
) - Commit your changes (
git commit -am 'Add some feature'
) - Push to the branch (
git push origin my-new-feature
) - Create new Pull Request