glob-regex
v0.3.2
Published
Tiny glob->regex converter
Downloads
711,311
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glob-regex
Convert a glob to a RegExp
object.
- Any periods are escaped (
.
->\\.
) *
and**
are replaced- Always start with
^
and end with$
- All
RegExp
syntax is valid - Path separators are auto-escaped by
new RegExp
const globRegex = require('glob-regex')
// Match no directory.
let re = globRegex('*.js')
re.test('a.js') // => true
re.test('a.css') // => false
re.test('a/b.js') // => false
// Use ? operator for optional character.
re = globRegex('*.jsx?')
re.test('a.js') // => true
re.test('b.jsx') // => true
// Match any directory.
re = globRegex('**.css')
re.test('a.css') // => true
re.test('a/b.css') // => true
// Match any directory and specific name.
re = globRegex('**/a.css')
re.test('a.css') // => true
re.test('b/a.css') // => true
// Use | operator to match multiple values.
re = globRegex('*.(js|css)')
re.test('a.js') // => true
re.test('a.css') // => true
Use globRegex.replace()
to transform a glob into a RegExp-compatible string.
NOTE: It's not recommended to use globRegex(array)
if you need
the exec
method, since the result will be difficult to make use of.
Using the test
method works great, though!