function-mock
v2.0.2
Published
Create a mock function which will return values based on arguments it's received
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function-mock
Intro
The intention of this module is to simplify mock functions in unit tests.
Sometimes it's not required or even detrimental to use tools, which allow calls counting, arguments recording etc. If you don't need all that functionality you may use an approach similar to this one: just define a behavior for a function, when it's called with particular arguments.
const functionMock = require('function-mock');
const fm = functionMock()
.with('foo').returns('1')
.with('bar').returns('2')
.withOther().throws('Some error message');
//returns '1'
fm('foo');
//returns '2'
fm('bar');
//throws
fm('bar', true);
Documentation v2.0.*
The imported module is a function, which when called returns a mock function. On itself it's not much useful.
const functionMock = require('function-mock');
const mocked = functionMock();
//returns undefined
mocked();
mocked
function's methods
This function has several methods:
.with(arg1?, arg2? …)
Accepts arguments which later will be matched against arguments provided to themocked(arg1?, arg2? …)
calls..withNew(arg1?, arg2? …)
The same as the.with()
method, except that arguments will be matched only if themocked
function is called with thenew
operator:new mocked(arg1?, arg2 …)
.withOther()
Used to provide a return or throw value for ordinary calls (without the new operator) where the arguments don't match any of the arguments previously provided with the.with()
or.withNew()
calls themocked(arg1?, arg2? …)
calls.const functionMock = require('function-mock'); let mocked = functionMock() .with(1).returns(2) .withOther().returns(0); //returns 0 mocked('not mathing value'); //returns 0 mocked(); mocked = functionMock() .with(1).returns(2) .withOther().throws('Some error message'); //throws 0 mocked(); //etc.
This method is supposed to be one of the last ones in the call chain. After it's called only the
.withOtherNew()
method will be available on the value returned from the.returns()
or.throws()
call.const mocked = functionMock() .with(1).returns(2) .withOther().returns(0); // this will throw, since no .with or .withNew methods available at //this point .with() .returns(1);
.withOtherNew()
The same as the.withOther()
method, except that will return/throw a value/error with a message provided to the subsequent.returns()
or.throws()
call only if the mock function has been called with thenew
operator..returns(value)
This method is intended to be called after a.with()
or similar method call:.with(…).returns(…)
. Makes the mocked function return the provided value if the arguments to its call match, (if called after.withNew()
then the value must be an object (not a primitive)):const functionMock = require('function-mock'); const mocked = functionMock().with(1).returns(2); //returns 2 mocked(1); const notPrimitive = []; mocked.withNew(1).returns(notPrimitive); //returns notPrimitive new mocked(1);
.throws(message)
analogous to.returns()
but throwsnew Error(message)
.
Call behavior with unmatched arguments
without the
new
operator, when the.withOther()
method hasn't been called:the mock function returns
undefined
if it's called with arguments which haven't matched arguments from any previous.with()
call:const mocked = functionMock() .with(1).returns(2) .with(1, 2).returns(3); //returns undefined mocked(2, 1);
without the
new
operator, when the.withOther()
method has been called:the mock function returns a value provided to a subsequent
.returns()
call, or throws an error with a message, provided to a subsequent.throws()
callconst mocked = functionMock() .with(1).returns(2) .with(1, 2).returns(3) .withOther().returns('foo'); //returns 'foo' mocked(2, 1);
with the
new
operator, when the.withOtherNew()
method hasn't been called:the mock function returns
undefined
if it's called with arguments which haven't matched arguments from any previous.withNew()
call:const retValueOne = []; const retValueTwo = {}; const mocked = functionMock() .withNew(1).returns(retValueOne) .withNew(1, 2).returns(retValueTwo); //returns {} (an instance of mocked) new mocked(2, 1);
with the
new
operator, when the.withOtherNew()
method has been called:the mock function returns/throws a value/error with a message provided to the subsequent
.returns()
/.throws()
call:const retValueOne = []; const retValueTwo = {}; const retValueDefault = {}; const mocked = functionMock() .withNew(1).returns(retValueOne) .withNew(1, 2).returns(retValueTwo) .withOtherNew().returns(retValueDefault); //returns retValueDefault new mocked(2, 1);
Arguments match rules
For all methods (.with()
& .withNew()
) the arguments matching rules are the
same (the only difference is that if a mocked function was called with or
without the new
operator) its arguments won't ever match arguments provided
to the .withNew()
/ .with()
methods respectively.
For instance:
const mocked = functionMock().with(1).returns(2);
//doesn't match, doesn't return 2
new mocked(1);
mocked.withNew(2).returns({});
//doesn't match, doesn't return {}
mocked(2);
the argument order matters:
const fm = functionMock().with(1, 2).returns(3); //doesn't match, doesn't return 3 fm(2, 1);
the amount of arguments matters:
const fm = functionMock().with(1).returns(3); //doesn't match, doesn't return 3 fm(1, 2);
primitive values are compared strictly
===
reference values are compared deeply by their leaf nodes:
const fm = functionMock().with([{foo: 'foo'}], 'bar').returns('match'); //matches, returns 'match' fm([{foo: 'foo',}], 'bar');
prototypes are counted, for instance:
class A { constructor() {} } //new A() will virtually produce a {} (an empty object w/o any own //properties) but it won't match a litteral {} const fm = functionMock().with(new A()).returns('match'); //doesn't match fm({}); //matches, returns 'match' fm(new A());
LICENSE
MIT