FizzBuzz.js

FizzBuzz solution for values n:m, w/optional divisors & text.

Return an array from values n:m for i, yielding [f] + [b] for value (n+i % div0) === 0 && (n+i % div1) === 0, yielding [f] for value (n+i % div0) === 0, yielding [b] for value (n+i % div1) === 0.

This solution to the FizzBuzz problem was inspired by a thread on Reddit about common frontend developer interview questions. I implemented a solution using a bodyless for-loop with heavy use of ternary operators.

This example was then turned into this Node module for even more concise code during an interview, where the developer can show his/her pragmatism and reluctance for "reinventing the wheel".

Usage

Simple usage:

$ npm install -s fizzbuzz.js

Then:

var fizzBuzz = require('fizzbuzz.js').fizzBuzz;
var results = fizzBuzz();

FizzBuzz takes optional arguments:

• n: (Number) Start value, default: 1
• m: (Number) End value, defalt: 100
• f: (String) Alternative Fizz string, default 'Fizz'
• b: (String) Alternative Buzz string, default 'Buzz'
• div0: (Number) Alternative first divisible value, default 3
• div1: (Number) Alternative second divisible value, default 5

This will return an array for values 1 to 100, for values divisible by 3 and 5.

var fizzBuzz = require('fizzbuzz.js').fizzBuzz;
var results = fizzBuzz(1, 100, 'Fizz', 'Buzz', 3, 5);

Returns an array with the following indexed values:

1 1
2 2
3 'Fizz'
4 4
5 'Buzz'
6 'Fizz'
7 7
8 8
9 'Fizz'
10 'Buzz'
11 11
12 'Fizz'
13 13
14 14
15 'FizzBuzz'
16 16
17 17
18 'Fizz'
19 19
20 'Buzz'
21 'Fizz'
22 22
23 23
24 'Fizz'
25 'Buzz'
26 26
27 'Fizz'
28 28
29 29
30 'FizzBuzz'
31 31
32 32
33 'Fizz'
34 34
35 'Buzz'
36 'Fizz'
37 37
38 38
39 'Fizz'
40 'Buzz'
41 41
42 'Fizz'
43 43
44 44
45 'FizzBuzz'
46 46
47 47
48 'Fizz'
49 49
50 'Buzz'
51 'Fizz'
52 52
53 53
54 'Fizz'
55 'Buzz'
56 56
57 'Fizz'
58 58
59 59
60 'FizzBuzz'
61 61
62 62
63 'Fizz'
64 64
65 'Buzz'
66 'Fizz'
67 67
68 68
69 'Fizz'
70 'Buzz'
71 71
72 'Fizz'
73 73
74 74
75 'FizzBuzz'
76 76
77 77
78 'Fizz'
79 79
80 'Buzz'
81 'Fizz'
82 82
83 83
84 'Fizz'
85 'Buzz'
86 86
87 'Fizz'
88 88
89 89
90 'FizzBuzz'
91 91
92 92
93 'Fizz'
94 94
95 'Buzz'
96 'Fizz'
97 97
98 98
99 'Fizz'
100 'Buzz'

Authors

• Ron. A - @0xadada

License

MIT