fantasy-land
v5.0.1
Published
Specification for interoperability of common algebraic structures in JavaScript
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Fantasy Land Specification
(aka "Algebraic JavaScript Specification")
This project specifies interoperability of common algebraic structures:
- Setoid
- Ord
- Semigroupoid
- Category
- Semigroup
- Monoid
- Group
- Filterable
- Functor
- Contravariant
- Apply
- Applicative
- Alt
- Plus
- Alternative
- Foldable
- Traversable
- Chain
- ChainRec
- Monad
- Extend
- Comonad
- Bifunctor
- Profunctor
General
An algebra is a set of values, a set of operators that it is closed under and some laws it must obey.
Each Fantasy Land algebra is a separate specification. An algebra may have dependencies on other algebras which must be implemented.
Terminology
- "value" is any JavaScript value, including any which have the structures defined below.
- "equivalent" is an appropriate definition of equivalence for the given value.
The definition should ensure that the two values can be safely swapped out in a program that respects abstractions. For example:
- Two lists are equivalent if they are equivalent at all indices.
- Two plain old JavaScript objects, interpreted as dictionaries, are equivalent when they are equivalent for all keys.
- Two promises are equivalent when they yield equivalent values.
- Two functions are equivalent if they yield equivalent outputs for equivalent inputs.
Type signature notation
The type signature notation used in this document is described below:1
::
"is a member of".e :: t
can be read as: "the expressione
is a member of typet
".true :: Boolean
- "true
is a member of typeBoolean
".42 :: Integer, Number
- "42
is a member of theInteger
andNumber
types".
- New types can be created via type constructors.
- Type constructors can take zero or more type arguments.
Array
is a type constructor which takes one type argument.Array String
is the type of all arrays of strings. Each of the following has typeArray String
:[]
,['foo', 'bar', 'baz']
.Array (Array String)
is the type of all arrays of arrays of strings. Each of the following has typeArray (Array String)
:[]
,[ [], [] ]
,[ [], ['foo'], ['bar', 'baz'] ]
.
- Lowercase letters stand for type variables.
- Type variables can take any type unless they have been restricted by means of type constraints (see fat arrow below).
->
(arrow) Function type constructor.->
is an infix type constructor that takes two type arguments where left argument is the input type and the right argument is the output type.->
's input type can be a grouping of types to create the type of a function which accepts zero or more arguments. The syntax is:(<input-types>) -> <output-type>
, where<input-types>
comprises zero or more comma–space (,
)-separated type representations and parens may be omitted for unary functions.String -> Array String
is a type satisfied by functions which take aString
and return anArray String
.String -> Array String -> Array String
is a type satisfied by functions which take aString
and return a function which takes anArray String
and returns anArray String
.(String, Array String) -> Array String
is a type satisfied by functions which take aString
and anArray String
as arguments and return anArray String
.() -> Number
is a type satisfied by functions which do not take arguments and return aNumber
.
~>
(squiggly arrow) Method type constructor.- When a function is a property of an Object, it is called a method. All methods have an implicit parameter type - the type of which they are a property.
a ~> a -> a
is a type satisfied by methods on Objects of typea
which take a typea
as an argument and return a value of typea
.
=>
(fat arrow) Expresses constraints on type variables.- In
a ~> a -> a
(see squiggly arrow above),a
can be of any type.Semigroup a => a ~> a -> a
adds a constraint such that the typea
must now satisfy theSemigroup
typeclass. To satisfy a typeclass means to lawfully implement all functions/methods specified by that typeclass.
- In
For example:
fantasy-land/traverse :: Applicative f, Traversable t => t a ~> (TypeRep f, a -> f b) -> f (t b)
'-------------------' '--------------------------' '-' '-------------------' '-----'
' ' ' ' '
' ' - type constraints ' ' - argument types ' - return type
' '
'- method name ' - method target type
Type representatives
Certain behaviours are defined from the perspective of a member of a type.
Other behaviours do not require a member. Thus certain algebras require a
type to provide a value-level representative (with certain properties). The
Identity type, for example, could provide Id
as its type representative:
Id :: TypeRep Identity
.
If a type provides a type representative, each member of the type must have
a constructor
property which is a reference to the type representative.
Algebras
Setoid
a['fantasy-land/equals'](a) === true
(reflexivity)a['fantasy-land/equals'](b) === b['fantasy-land/equals'](a)
(symmetry)- If
a['fantasy-land/equals'](b)
andb['fantasy-land/equals'](c)
, thena['fantasy-land/equals'](c)
(transitivity)
fantasy-land/equals
method
fantasy-land/equals :: Setoid a => a ~> a -> Boolean
A value which has a Setoid must provide a fantasy-land/equals
method. The
fantasy-land/equals
method takes one argument:
a['fantasy-land/equals'](b)
b
must be a value of the same Setoid- If
b
is not the same Setoid, behaviour offantasy-land/equals
is unspecified (returningfalse
is recommended).
- If
fantasy-land/equals
must return a boolean (true
orfalse
).
Ord
A value that implements the Ord specification must also implement the Setoid specification.
a['fantasy-land/lte'](b)
orb['fantasy-land/lte'](a)
(totality)- If
a['fantasy-land/lte'](b)
andb['fantasy-land/lte'](a)
, thena['fantasy-land/equals'](b)
(antisymmetry) - If
a['fantasy-land/lte'](b)
andb['fantasy-land/lte'](c)
, thena['fantasy-land/lte'](c)
(transitivity)
fantasy-land/lte
method
fantasy-land/lte :: Ord a => a ~> a -> Boolean
A value which has an Ord must provide a fantasy-land/lte
method. The
fantasy-land/lte
method takes one argument:
a['fantasy-land/lte'](b)
b
must be a value of the same Ord- If
b
is not the same Ord, behaviour offantasy-land/lte
is unspecified (returningfalse
is recommended).
- If
fantasy-land/lte
must return a boolean (true
orfalse
).
Semigroupoid
a['fantasy-land/compose'](b)['fantasy-land/compose'](c) === a['fantasy-land/compose'](b['fantasy-land/compose'](c))
(associativity)
fantasy-land/compose
method
fantasy-land/compose :: Semigroupoid c => c i j ~> c j k -> c i k
A value which has a Semigroupoid must provide a fantasy-land/compose
method. The
fantasy-land/compose
method takes one argument:
a['fantasy-land/compose'](b)
b
must be a value of the same Semigroupoid- If
b
is not the same semigroupoid, behaviour offantasy-land/compose
is unspecified.
- If
fantasy-land/compose
must return a value of the same Semigroupoid.
Category
A value that implements the Category specification must also implement the Semigroupoid specification.
a['fantasy-land/compose'](C['fantasy-land/id']())
is equivalent toa
(right identity)C['fantasy-land/id']()['fantasy-land/compose'](a)
is equivalent toa
(left identity)
fantasy-land/id
method
fantasy-land/id :: Category c => () -> c a a
A value which has a Category must provide a fantasy-land/id
function on its
type representative:
C['fantasy-land/id']()
Given a value c
, one can access its type representative via the
constructor
property:
c.constructor['fantasy-land/id']()
fantasy-land/id
must return a value of the same Category
Semigroup
a['fantasy-land/concat'](b)['fantasy-land/concat'](c)
is equivalent toa['fantasy-land/concat'](b['fantasy-land/concat'](c))
(associativity)
fantasy-land/concat
method
fantasy-land/concat :: Semigroup a => a ~> a -> a
A value which has a Semigroup must provide a fantasy-land/concat
method. The
fantasy-land/concat
method takes one argument:
s['fantasy-land/concat'](b)
b
must be a value of the same Semigroup- If
b
is not the same semigroup, behaviour offantasy-land/concat
is unspecified.
- If
fantasy-land/concat
must return a value of the same Semigroup.
Monoid
A value that implements the Monoid specification must also implement the Semigroup specification.
m['fantasy-land/concat'](M['fantasy-land/empty']())
is equivalent tom
(right identity)M['fantasy-land/empty']()['fantasy-land/concat'](m)
is equivalent tom
(left identity)
fantasy-land/empty
method
fantasy-land/empty :: Monoid m => () -> m
A value which has a Monoid must provide a fantasy-land/empty
function on its
type representative:
M['fantasy-land/empty']()
Given a value m
, one can access its type representative via the
constructor
property:
m.constructor['fantasy-land/empty']()
fantasy-land/empty
must return a value of the same Monoid
Group
A value that implements the Group specification must also implement the Monoid specification.
g['fantasy-land/concat'](g['fantasy-land/invert']())
is equivalent tog.constructor['fantasy-land/empty']()
(right inverse)g['fantasy-land/invert']()['fantasy-land/concat'](g)
is equivalent tog.constructor['fantasy-land/empty']()
(left inverse)
fantasy-land/invert
method
fantasy-land/invert :: Group g => g ~> () -> g
A value which has a Group must provide a fantasy-land/invert
method. The
fantasy-land/invert
method takes no arguments:
g['fantasy-land/invert']()
fantasy-land/invert
must return a value of the same Group.
Filterable
v['fantasy-land/filter'](x => p(x) && q(x))
is equivalent tov['fantasy-land/filter'](p)['fantasy-land/filter'](q)
(distributivity)v['fantasy-land/filter'](x => true)
is equivalent tov
(identity)v['fantasy-land/filter'](x => false)
is equivalent tow['fantasy-land/filter'](x => false)
ifv
andw
are values of the same Filterable (annihilation)
fantasy-land/filter
method
fantasy-land/filter :: Filterable f => f a ~> (a -> Boolean) -> f a
A value which has a Filterable must provide a fantasy-land/filter
method. The fantasy-land/filter
method takes one argument:
v['fantasy-land/filter'](p)
p
must be a function.- If
p
is not a function, the behaviour offantasy-land/filter
is unspecified. p
must return eithertrue
orfalse
. If it returns any other value, the behaviour offantasy-land/filter
is unspecified.
- If
fantasy-land/filter
must return a value of the same Filterable.
Functor
u['fantasy-land/map'](a => a)
is equivalent tou
(identity)u['fantasy-land/map'](x => f(g(x)))
is equivalent tou['fantasy-land/map'](g)['fantasy-land/map'](f)
(composition)
fantasy-land/map
method
fantasy-land/map :: Functor f => f a ~> (a -> b) -> f b
A value which has a Functor must provide a fantasy-land/map
method. The fantasy-land/map
method takes one argument:
u['fantasy-land/map'](f)
f
must be a function,- If
f
is not a function, the behaviour offantasy-land/map
is unspecified. f
can return any value.- No parts of
f
's return value should be checked.
- If
fantasy-land/map
must return a value of the same Functor
Contravariant
u['fantasy-land/contramap'](a => a)
is equivalent tou
(identity)u['fantasy-land/contramap'](x => f(g(x)))
is equivalent tou['fantasy-land/contramap'](f)['fantasy-land/contramap'](g)
(composition)
fantasy-land/contramap
method
fantasy-land/contramap :: Contravariant f => f a ~> (b -> a) -> f b
A value which has a Contravariant must provide a fantasy-land/contramap
method. The
fantasy-land/contramap
method takes one argument:
u['fantasy-land/contramap'](f)
f
must be a function,- If
f
is not a function, the behaviour offantasy-land/contramap
is unspecified. f
can return any value.- No parts of
f
's return value should be checked.
- If
fantasy-land/contramap
must return a value of the same Contravariant
Apply
A value that implements the Apply specification must also implement the Functor specification.
v['fantasy-land/ap'](u['fantasy-land/ap'](a['fantasy-land/map'](f => g => x => f(g(x)))))
is equivalent tov['fantasy-land/ap'](u)['fantasy-land/ap'](a)
(composition)
fantasy-land/ap
method
fantasy-land/ap :: Apply f => f a ~> f (a -> b) -> f b
A value which has an Apply must provide a fantasy-land/ap
method. The fantasy-land/ap
method takes one argument:
a['fantasy-land/ap'](b)
b
must be an Apply of a function- If
b
does not represent a function, the behaviour offantasy-land/ap
is unspecified. b
must be same Apply asa
.
- If
a
must be an Apply of any valuefantasy-land/ap
must apply the function in Applyb
to the value in Applya
- No parts of return value of that function should be checked.
The
Apply
returned byfantasy-land/ap
must be the same asa
andb
Applicative
A value that implements the Applicative specification must also implement the Apply specification.
v['fantasy-land/ap'](A['fantasy-land/of'](x => x))
is equivalent tov
(identity)A['fantasy-land/of'](x)['fantasy-land/ap'](A['fantasy-land/of'](f))
is equivalent toA['fantasy-land/of'](f(x))
(homomorphism)A['fantasy-land/of'](y)['fantasy-land/ap'](u)
is equivalent tou['fantasy-land/ap'](A['fantasy-land/of'](f => f(y)))
(interchange)
fantasy-land/of
method
fantasy-land/of :: Applicative f => a -> f a
A value which has an Applicative must provide a fantasy-land/of
function on its
type representative. The fantasy-land/of
function takes
one argument:
F['fantasy-land/of'](a)
Given a value f
, one can access its type representative via the
constructor
property:
f.constructor['fantasy-land/of'](a)
fantasy-land/of
must provide a value of the same Applicative- No parts of
a
should be checked
- No parts of
Alt
A value that implements the Alt specification must also implement the Functor specification.
a['fantasy-land/alt'](b)['fantasy-land/alt'](c)
is equivalent toa['fantasy-land/alt'](b['fantasy-land/alt'](c))
(associativity)a['fantasy-land/alt'](b)['fantasy-land/map'](f)
is equivalent toa['fantasy-land/map'](f)['fantasy-land/alt'](b['fantasy-land/map'](f))
(distributivity)
fantasy-land/alt
method
fantasy-land/alt :: Alt f => f a ~> f a -> f a
A value which has a Alt must provide a fantasy-land/alt
method. The
fantasy-land/alt
method takes one argument:
a['fantasy-land/alt'](b)
b
must be a value of the same Alt- If
b
is not the same Alt, behaviour offantasy-land/alt
is unspecified. a
andb
can contain any value of same type.- No parts of
a
's andb
's containing value should be checked.
- If
fantasy-land/alt
must return a value of the same Alt.
Plus
A value that implements the Plus specification must also implement the Alt specification.
x['fantasy-land/alt'](A['fantasy-land/zero']())
is equivalent tox
(right identity)A['fantasy-land/zero']()['fantasy-land/alt'](x)
is equivalent tox
(left identity)A['fantasy-land/zero']()['fantasy-land/map'](f)
is equivalent toA['fantasy-land/zero']()
(annihilation)
fantasy-land/zero
method
fantasy-land/zero :: Plus f => () -> f a
A value which has a Plus must provide a fantasy-land/zero
function on its
type representative:
A['fantasy-land/zero']()
Given a value x
, one can access its type representative via the
constructor
property:
x.constructor['fantasy-land/zero']()
fantasy-land/zero
must return a value of the same Plus
Alternative
A value that implements the Alternative specification must also implement the Applicative and Plus specifications.
x['fantasy-land/ap'](f['fantasy-land/alt'](g))
is equivalent tox['fantasy-land/ap'](f)['fantasy-land/alt'](x['fantasy-land/ap'](g))
(distributivity)x['fantasy-land/ap'](A['fantasy-land/zero']())
is equivalent toA['fantasy-land/zero']()
(annihilation)
Foldable
u['fantasy-land/reduce']
is equivalent tou['fantasy-land/reduce']((acc, x) => acc.concat([x]), []).reduce
fantasy-land/reduce
method
fantasy-land/reduce :: Foldable f => f a ~> ((b, a) -> b, b) -> b
A value which has a Foldable must provide a fantasy-land/reduce
method. The fantasy-land/reduce
method takes two arguments:
u['fantasy-land/reduce'](f, x)
f
must be a binary function- if
f
is not a function, the behaviour offantasy-land/reduce
is unspecified. - The first argument to
f
must be the same type asx
. f
must return a value of the same type asx
.- No parts of
f
's return value should be checked.
- if
x
is the initial accumulator value for the reduction- No parts of
x
should be checked.
- No parts of
Traversable
A value that implements the Traversable specification must also implement the Functor and Foldable specifications.
t(u['fantasy-land/traverse'](F, x => x))
is equivalent tou['fantasy-land/traverse'](G, t)
for anyt
such thatt(a)['fantasy-land/map'](f)
is equivalent tot(a['fantasy-land/map'](f))
(naturality)u['fantasy-land/traverse'](F, F['fantasy-land/of'])
is equivalent toF['fantasy-land/of'](u)
for any ApplicativeF
(identity)u['fantasy-land/traverse'](Compose, x => new Compose(x))
is equivalent tonew Compose(u['fantasy-land/traverse'](F, x => x)['fantasy-land/map'](x => x['fantasy-land/traverse'](G, x => x)))
forCompose
defined below and any ApplicativesF
andG
(composition)
function Compose(c) {
this.c = c;
}
Compose['fantasy-land/of'] = function(x) {
return new Compose(F['fantasy-land/of'](G['fantasy-land/of'](x)));
};
Compose.prototype['fantasy-land/ap'] = function(f) {
return new Compose(this.c['fantasy-land/ap'](f.c['fantasy-land/map'](u => y => y['fantasy-land/ap'](u))));
};
Compose.prototype['fantasy-land/map'] = function(f) {
return new Compose(this.c['fantasy-land/map'](y => y['fantasy-land/map'](f)));
};
fantasy-land/traverse
method
fantasy-land/traverse :: Applicative f, Traversable t => t a ~> (TypeRep f, a -> f b) -> f (t b)
A value which has a Traversable must provide a fantasy-land/traverse
method. The fantasy-land/traverse
method takes two arguments:
u['fantasy-land/traverse'](A, f)
A
must be the type representative of an Applicative.f
must be a function which returns a value- If
f
is not a function, the behaviour offantasy-land/traverse
is unspecified. f
must return a value of the type represented byA
.
- If
fantasy-land/traverse
must return a value of the type represented byA
.
Chain
A value that implements the Chain specification must also implement the Apply specification.
m['fantasy-land/chain'](f)['fantasy-land/chain'](g)
is equivalent tom['fantasy-land/chain'](x => f(x)['fantasy-land/chain'](g))
(associativity)
fantasy-land/chain
method
fantasy-land/chain :: Chain m => m a ~> (a -> m b) -> m b
A value which has a Chain must provide a fantasy-land/chain
method. The fantasy-land/chain
method takes one argument:
m['fantasy-land/chain'](f)
f
must be a function which returns a value- If
f
is not a function, the behaviour offantasy-land/chain
is unspecified. f
must return a value of the same Chain
- If
fantasy-land/chain
must return a value of the same Chain
ChainRec
A value that implements the ChainRec specification must also implement the Chain specification.
M['fantasy-land/chainRec']((next, done, v) => p(v) ? d(v)['fantasy-land/map'](done) : n(v)['fantasy-land/map'](next), i)
is equivalent to(function step(v) { return p(v) ? d(v) : n(v)['fantasy-land/chain'](step); }(i))
(equivalence)- Stack usage of
M['fantasy-land/chainRec'](f, i)
must be at most a constant multiple of the stack usage off
itself.
fantasy-land/chainRec
method
fantasy-land/chainRec :: ChainRec m => ((a -> c, b -> c, a) -> m c, a) -> m b
A Type which has a ChainRec must provide a fantasy-land/chainRec
function on its
type representative. The fantasy-land/chainRec
function
takes two arguments:
M['fantasy-land/chainRec'](f, i)
Given a value m
, one can access its type representative via the
constructor
property:
m.constructor['fantasy-land/chainRec'](f, i)
f
must be a function which returns a value- If
f
is not a function, the behaviour offantasy-land/chainRec
is unspecified. f
takes three argumentsnext
,done
,value
next
is a function which takes one argument of same type asi
and can return any valuedone
is a function which takes one argument and returns the same type as the return value ofnext
value
is some value of the same type asi
f
must return a value of the same ChainRec which contains a value returned from eitherdone
ornext
- If
fantasy-land/chainRec
must return a value of the same ChainRec which contains a value of same type as argument ofdone
Monad
A value that implements the Monad specification must also implement the Applicative and Chain specifications.
M['fantasy-land/of'](a)['fantasy-land/chain'](f)
is equivalent tof(a)
(left identity)m['fantasy-land/chain'](M['fantasy-land/of'])
is equivalent tom
(right identity)
Extend
A value that implements the Extend specification must also implement the Functor specification.
w['fantasy-land/extend'](g)['fantasy-land/extend'](f)
is equivalent tow['fantasy-land/extend'](_w => f(_w['fantasy-land/extend'](g)))
fantasy-land/extend
method
fantasy-land/extend :: Extend w => w a ~> (w a -> b) -> w b
An Extend must provide a fantasy-land/extend
method. The fantasy-land/extend
method takes one argument:
w['fantasy-land/extend'](f)
f
must be a function which returns a value- If
f
is not a function, the behaviour offantasy-land/extend
is unspecified. f
must return a value of typev
, for some variablev
contained inw
.- No parts of
f
's return value should be checked.
- If
fantasy-land/extend
must return a value of the same Extend.
Comonad
A value that implements the Comonad specification must also implement the Extend specification.
w['fantasy-land/extend'](_w => _w['fantasy-land/extract']())
is equivalent tow
(left identity)w['fantasy-land/extend'](f)['fantasy-land/extract']()
is equivalent tof(w)
(right identity)
fantasy-land/extract
method
fantasy-land/extract :: Comonad w => w a ~> () -> a
A value which has a Comonad must provide a fantasy-land/extract
method on itself.
The fantasy-land/extract
method takes no arguments:
w['fantasy-land/extract']()
fantasy-land/extract
must return a value of typev
, for some variablev
contained inw
.v
must have the same type thatf
returns infantasy-land/extend
.
Bifunctor
A value that implements the Bifunctor specification must also implement the Functor specification.
p['fantasy-land/bimap'](a => a, b => b)
is equivalent top
(identity)p['fantasy-land/bimap'](a => f(g(a)), b => h(i(b))
is equivalent top['fantasy-land/bimap'](g, i)['fantasy-land/bimap'](f, h)
(composition)
fantasy-land/bimap
method
fantasy-land/bimap :: Bifunctor f => f a c ~> (a -> b, c -> d) -> f b d
A value which has a Bifunctor must provide a fantasy-land/bimap
method. The fantasy-land/bimap
method takes two arguments:
c['fantasy-land/bimap'](f, g)
f
must be a function which returns a value- If
f
is not a function, the behaviour offantasy-land/bimap
is unspecified. f
can return any value.- No parts of
f
's return value should be checked.
- If
g
must be a function which returns a value- If
g
is not a function, the behaviour offantasy-land/bimap
is unspecified. g
can return any value.- No parts of
g
's return value should be checked.
- If
fantasy-land/bimap
must return a value of the same Bifunctor.
Profunctor
A value that implements the Profunctor specification must also implement the Functor specification.
p['fantasy-land/promap'](a => a, b => b)
is equivalent top
(identity)p['fantasy-land/promap'](a => f(g(a)), b => h(i(b)))
is equivalent top['fantasy-land/promap'](f, i)['fantasy-land/promap'](g, h)
(composition)
fantasy-land/promap
method
fantasy-land/promap :: Profunctor p => p b c ~> (a -> b, c -> d) -> p a d
A value which has a Profunctor must provide a fantasy-land/promap
method.
The fantasy-land/promap
method takes two arguments:
c['fantasy-land/promap'](f, g)
f
must be a function which returns a value- If
f
is not a function, the behaviour offantasy-land/promap
is unspecified. f
can return any value.- No parts of
f
's return value should be checked.
- If
g
must be a function which returns a value- If
g
is not a function, the behaviour offantasy-land/promap
is unspecified. g
can return any value.- No parts of
g
's return value should be checked.
- If
fantasy-land/promap
must return a value of the same Profunctor
Derivations
When creating data types which satisfy multiple algebras, authors may choose to implement certain methods then derive the remaining methods. Derivations:
fantasy-land/equals
may be derived fromfantasy-land/lte
:function equals(other) { return this['fantasy-land/lte'](other) && other['fantasy-land/lte'](this); }
fantasy-land/map
may be derived fromfantasy-land/ap
andfantasy-land/of
:function map(f) { return this['fantasy-land/ap'](this.constructor['fantasy-land/of'](f)); }
fantasy-land/map
may be derived fromfantasy-land/chain
andfantasy-land/of
:function map(f) { return this['fantasy-land/chain'](a => this.constructor['fantasy-land/of'](f(a))); }
fantasy-land/map
may be derived fromfantasy-land/bimap
:function map(f) { return this['fantasy-land/bimap'](a => a, f); }
fantasy-land/map
may be derived fromfantasy-land/promap
:function map(f) { return this['fantasy-land/promap'](a => a, f); }
fantasy-land/ap
may be derived fromfantasy-land/chain
:function ap(m) { return m['fantasy-land/chain'](f => this['fantasy-land/map'](f)); }
fantasy-land/reduce
may be derived as follows:function reduce(f, acc) { function Const(value) { this.value = value; } Const['fantasy-land/of'] = function(_) { return new Const(acc); }; Const.prototype['fantasy-land/map'] = function(_) { return this; }; Const.prototype['fantasy-land/ap'] = function(b) { return new Const(f(b.value, this.value)); }; return this['fantasy-land/traverse'](x => new Const(x), Const['fantasy-land/of']).value; }
fantasy-land/map
may be derived as follows:function map(f) { function Id(value) { this.value = value; } Id['fantasy-land/of'] = function(x) { return new Id(x); }; Id.prototype['fantasy-land/map'] = function(f) { return new Id(f(this.value)); }; Id.prototype['fantasy-land/ap'] = function(b) { return new Id(this.value(b.value)); }; return this['fantasy-land/traverse'](x => Id['fantasy-land/of'](f(x)), Id['fantasy-land/of']).value; }
fantasy-land/filter
may be derived fromfantasy-land/of
,fantasy-land/chain
, andfantasy-land/zero
:function filter(pred) { var F = this.constructor; return this['fantasy-land/chain'](x => pred(x) ? F['fantasy-land/of'](x) : F['fantasy-land/zero']()); }
fantasy-land/filter
may be derived fromfantasy-land/concat
,fantasy-land/of
,fantasy-land/zero
, andfantasy-land/reduce
:function filter(pred) { var F = this.constructor; return this['fantasy-land/reduce']((f, x) => pred(x) ? f['fantasy-land/concat'](F['fantasy-land/of'](x)) : f, F['fantasy-land/zero']()); }
If a data type provides a method which could be derived, its behaviour must be equivalent to that of the derivation (or derivations).
Notes
- If there's more than a single way to implement the methods and laws, the implementation should choose one and provide wrappers for other uses.
- It's discouraged to overload the specified methods. It can easily result in broken and buggy behaviour.
- It is recommended to throw an exception on unspecified behaviour.
- An
Identity
container which implements many of the methods is provided by sanctuary-identity.
Alternatives
There also exists Static Land Specification with exactly the same ideas as Fantasy Land but based on static methods instead of instance methods.