deep-type-check
v1.0.2
Published
Runtime type checking with "value as type" model definition in Javascript.
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deep-type-check
Runtime type deep-checking with value as type
model definition in Javascript.
Installation
npm i deep-type-check
Motivation
Runtime type checking in Javascript has always been a pain-point even for some veterans. With the help of Typescript type annotation, and some modern Javascript feature such as optional chaining, this issue has been alleviated . But for some cases, there is still no simple way. For instance:
interface User {
name: string;
hobby: string[];
}
const { body } = await fetch('/user/:id')
// body = { "name": "peter", hobby: "badminton" }
const user: User = JSON.parse(body)
user.hobby.forEach((h) => { console.log(h) })
// Uncaught TypeError: user.hobby.forEach is not a function
We can have everything concretely typed throughout our code-base, but response from API is always a risk to break our app at runtime. To secure our app at runtime, we might do something like below, the more properties we want to check, the more tedious code we need to write.
// runtime type checking
if (user.hobby instanceof 'Array') {
user.hobby.forEach(() => {})
} else {
throw 'not good response from API'
}
What if we can do something like this?
if (check(userModel, userData)) {
}
Quick Start
Declare runtime model definition using value as type
. The non-currying way:
import { check } from 'deep-type-check'
const modelA = {
foo: 0 // number type
}
const modelB = {
foo: '' // string type
}
const data = {
foo: 3.14
}
check(modelA, data) // => true
check(modelB, data) // => false
The currying way:
const data = {
foo: 3.14
}
const typeCheckerA = check({ foo: 0 })
const typeCheckerB = check({ foo: '' })
typeCheckerA(data) // => true
typeCheckerB(data) // => false
Usage
Pass whatever type you want to check.
check('', '') // => true
check(null, '') // => false
check(undefined, '') // => false
check(1, '') // => false
check(true, '') // => false
check([], '') // => false
check({}, '') // => false
Required
All object properties declared are required by default.
const model = { a: 1 }
check(model, {}) // => false, missing property "a"
Optional
Making property optional.
import { check, optional } from "deep-type-check";
const model = { a: optional(1) }
check(model, {}) // => true, property "a" is optional
Or you can just mark a type as optional.
check(optional(1), undefined)
// => true
Making null
or undefined
optional does not make sense, so:
check({ a: optional(null) })
// => Error 'optional does not accept null or undefined'
Any type
For any type, use the magic string any
.
check('any', null) // => true
check('any', undefined) // => true
check('any', 1) // => true
check('any', '') // => true
check('any', true) // => true
check('any', []) // => true
check('any', {}) // => true
check({ a: 'any' }, { a: 1 }) // => true
check({ a: 'any' }, { a: '' }) // => true
check(['any'], [1]) // => true
check(['any'], ['1']) // => true
Recursive vs non-recursive
Function check
will do the deep-check by default. Using the shallowCheck
for non-recursive mode.
import { check, shallowCheck } from 'deep-type-check'
check([[1]], [['1']])
// => false, type mismatch of nested array
check({
a: { b: 1 }
}, {
a: { b: '1' }
})
// => false, type mismatch of nested object
shallowCheck([[1]], [['1']])
// => true, shallow check won't go recursively
shallowCheck({
a: { b: 1 }
}, {
a: { b: '1' }
})
// => true, shallow check won't go recursively
Array with multiple types
A similar implementation to the tuple type in Typescript.
// the array accept both number and string as its item's type
check([1, ''], ['foo']) // => true
check([1, ''], [9]) // => true
check([1, ''], [9, 'foo']) // => true
check([1, ''], ['foo', 9]) // => true