basic-xml2json

Simple parser to convert XML strings to JSON.

Usage

var xml2json = require('basic-xml2json');

parse

This code is based off the xml-parser here: https://github.com/segmentio/xml-parser. Please see that page for details of the JSON output.

The parse function takes an XML string (mandatory) and an object describing the options (optional).

var json = xml2json.parse(xml, options);

Or

var json = xml2json.parse(xml);

parse:options

• removeNamespacePrefixes

  Boolean, defaults to true. Set this to false if you want to retain xml namespace prefixes in the JSON output.

  var options = { removeNamespacePrefixes: false };
  	

getChildNodes

Get an array of matching nodes under the specified parent node for the specified path.

var json = xml2json.parse(xml);
var nodes = xml2json.getChildNodes(json.root, ['Body','Response','Address']);
	

getChildNode

Get the first matching node under the specified parent node for the specified path.

var json = xml2json.parse(xml);
var address = xml2json.getChildNode(json.root, ['Body','Response','Address']);
	

getContent

Get the value of the first matching node under the specified parent node for the specified path. Encoded XML values will are decoded.

var json = xml2json.parse(xml);
var address = xml2json.getChildNode(json.root, ['Body','Response','Address']);
var suburb = xml2json.getContent(address, 'Suburb');

Or var suburb = xml2json.getContent(json.root, ['Body','Response','Address','Suburb']);

getRawContent

Just like getContent except that encoded XML values are not decoded.

var suburb = xml2json.getRawContent(json.root, ['Body','Response','Address','Suburb']);
	

getAllContent

Get an array of values for the matching nodes under the specified parent node for the specified path. Encoded XML values will are decoded.

var json = xml2json.parse(xml);
var suburbs = xml2json.getAllContent(json.root, ['Body','Response','Address','Suburb']);

decodeXML

Decode some text.

var decodedText = decodeXML(text);

encodeXML

Encode some text.

var encodedText = encodeXML(text);

Wildcard Matching

Probably rarely useful, but if you have a situation where you need to match elements with different paths (but at the same depth) then you can use a wildcard match. For example:

<xmldoc>
	<postalAddress>
		<suburb>Brisbane</suburb>
	</postalAddress>
	<billingAddress>
		<suburb>Sydney</suburb>
	</billingAddress>
</xmldoc>

var json = xml2json.parse(xml);
var suburbs = xml2json.getAllContent(json.root, [xml2json.ANY, 'suburb']);

In this example, suburbs will be ['Brisbane','Sydney'].