base-x-bytearray
v0.1.3
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Fast base encoding / decoding of any given alphabet to Uint8Array/Buffer
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base-x
Fast base encoding / decoding of any given alphabet using bitcoin style leading zero compression.
This is forked from cryptocoinjs/base-x
And simply uses Uint8array if Buffer isn't already available.
Example
Base58
var BASE58 = '123456789ABCDEFGHJKLMNPQRSTUVWXYZabcdefghijkmnopqrstuvwxyz'
var bs58 = require('base-x')(BASE58)
var decoded = bs58.decode('5Kd3NBUAdUnhyzenEwVLy9pBKxSwXvE9FMPyR4UKZvpe6E3AgLr')
console.log(decoded)
// => <Uint8array- 80 ed db dc 11 68 f1 da ea db d3 e4 4c 1e 3f 8f 5a 28 4c 20 29 f7 8a d2 6a f9 85 83 a4 99 de 5b 19>
console.log(bs58.encode(decoded))
// => 5Kd3NBUAdUnhyzenEwVLy9pBKxSwXvE9FMPyR4UKZvpe6E3AgLr
Alphabets
See below for a list of commonly recognized alphabets, and their respective base.
Base | Alphabet
------------- | -------------
2 | 01
8 | 01234567
11 | 0123456789a
16 | 0123456789abcdef
32 | 0123456789ABCDEFGHJKMNPQRSTVWXYZ
36 | 0123456789abcdefghijklmnopqrstuvwxyz
58 | 123456789ABCDEFGHJKLMNPQRSTUVWXYZabcdefghijkmnopqrstuvwxyz
62 | 0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ
64 | ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/
66 | ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789-_.!~
How it works
It encodes octet arrays by doing long divisions on all significant digits in the array, creating a representation of that number in the new base. Then for every leading zero in the input (not significant as a number) it will encode as a single leader character. This is the first in the alphabet and will decode as 8 bits. The other characters depend upon the base. For example, a base58 alphabet packs roughly 5.858 bits per character.
This means the encoded string 000f (using a 0-f alphabet) will actually decode to 4 bytes unlike a typical hex codec which uniformly packs 4 bits into each character.
While unusual, this does mean that no padding is required and it works for bases like 43. If you need standard hex encoding or base64 encoding you probably don't want this.
The algorithm used to convert the base of the number is roughly this:
significant = 12345
base = 16
digits = []
while significant > base:
significant, remainder = divmod(significant, base)
digits.append(remainder)
digits.append(significant)
assert list(reversed(digits)) == [3,0,3,9]
assert hex(12345) == '0x3039'
Of course the input is actually an array of digits already :)
License
This library is free and open-source software released under the MIT license.