array-math

modularity

Sorry, I built this before I learned the truth about modularity. See the following links for enlightenment. ;-)

• http://substack.net/finding_modules
• http://substack.net/how_I_write_modules
• http://substack.net/many_things

api

var aMath = require('array-math')

aMath.factors(n)

If you only want this function, try primefactors.

• n must be a positive integer

aMath.factors(2)   // -> [2]
aMath.factors(96)  // -> [2, 2, 2, 2, 2, 3]
aMath.factors(100) // -> [2, 2, 5, 5]

aMath.divisors(n[, opts])

If you only want this function, you could factor it out, and send me a PR with a link to your module! (Grab the test file while you're at it.)

• n must be a positive number.
• opts is an object with the options. Defaults to {}.
  • proper can be inside opts. If true, it will make the resulting array not include n. Defaults to false.

aMath.divisors(2)                  // -> [2]
aMath.divisors(96)                 // -> [1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96]
aMath.divisors(100)                // -> [1, 2, 4, 5, 10, 20, 25, 50, 100]
aMath.divisors(100, {proper:true}) // -> [1, 2, 4, 5, 10, 20, 25, 50]

aMath.isPrime(n)

If you only want this function, try isprime.

• n must be a positive integer

aMath.isPrime(2)   // -> true
aMath.isPrime(3)   // -> true
aMath.isPrime(4)   // -> false
aMath.isPrime(7)   // -> true
aMath.isPrime(96)  // -> false
aMath.isPrime(97)  // -> true
aMath.isPrime(100) // -> false
aMath.isPrime(113) // -> true
aMath.isPrime(117) // -> false

aMath.range([start,] stop [,step])

If you only want this function, try array-range. (Does not have stepping built in.)

• start is the starting number of the range. Defaults to 0. If there are 2 or 3 arguments, this is assumed to be the first.
• stop is the ending number of the range. Defaults to 0. If there is 1 argument, this is assumed to be it.
• step is the step between each number. Defaults to 1. This is may not be 0, and is set to 1 if it is.

aMath.range()      // -> []
aMath.range(0)     // -> []
aMath.range(1)     // -> [0]
aMath.range(2)     // -> [0, 1]
aMath.range(2, 2)  // -> []
aMath.range(2, 3)  // -> [2]
aMath.range(3)     // -> [0, 1, 2]
aMath.range(10)    // -> [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
aMath.range(2, 10) // -> [2, 3, 4, 5, 6, 7, 8, 9]
aMath.range(5, 10) // -> [5, 6, 7, 8, 9]

aMath.multiply(a)

If you only want this function, it might be best to just write it yourself:

arr.reduce(function (prdct, fctr) { return prdct * fctr }, 1)

• a must be an array of numbers (integers, floats, negative, whatever).

aMath.multiply([2, 96, 100])         // -> 19200
aMath.multiply([40, 3, 17])          // -> 2040
aMath.multiply([4, 5, 2, 5.2, 3.8])  // -> 790.4
aMath.multiply([520, 0.2, 0.2, 0.8]) // -> 16.64

aMath.sum(a)

If you only want this function, it might be best to just write it yourself:

arr.reduce(function (sum, val) { return sum + val }, 0)

• a must be an array of numbers (integers, floats, negative, whatever).

aMath.sum([2, 96, 100])  // -> 198
aMath.sum([2, -96, 100]) // -> 6
aMath.sum([45, 20, 8.3]) // -> 73.3

aMath.factorial(h[, l])

If you only want this function, try factorial. (Does not have low number built in.)

• h must be a number. It is the high number. It defaults to 0.
• l must be a number. It is the low number. It defaults to 0.
  While multiplying, it will never multiply by 0.

aMath.factorial()      // -> 1
aMath.factorial(0)     // -> 1
aMath.factorial(1)     // -> 1
aMath.factorial(2)     // -> 2         (2x1)
aMath.factorial(3)     // -> 6         (3x2x1)
aMath.factorial(5)     // -> 120       (5x4x3x2x1)
aMath.factorial(5, 0)  // -> 120       (5x4x3x2x1)
aMath.factorial(5, 1)  // -> 120       (5x4x3x2x1)
aMath.factorial(5, 2)  // -> 120       (5x4x3x2)
aMath.factorial(5, 3)  // -> 60        (5x4x3)
aMath.factorial(5, 4)  // -> 20        (5x4)
aMath.factorial(10)    // -> 3628800   (10x9x8x7x6x5x4x3x2x1)
aMath.factorial(10, 3) // -> 1814400   (10x9x8x7x6x5x4x3)
aMath.factorial(10, 5) // -> 151200    (10x9x8x7x6x5)

install

Install with NPM

npm install array-math

license

VOL