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@superjs/lazy

v1.0.1

Published

lazy object

Downloads

6

Readme

@superjs/lazy

lazy object.

Thought

If you want to define some lazy variable, you can either:

  1. define a function instead, which is ugly
  2. use a function to define a variable, such as let local= lazy({a:()=>new Date()}), then use it as local.a

Example

const lazy = require('@superjs/lazy')
const lazyLocal = lazy({
  noLazy: new Date(),
  lazy: ()=>{
    console.log('lazy')
    return new Date()
  },
  lazyNeverHappen: ()=>{
    console.log('lazyNeverHappen')
    return new Date()
  },
})

console.log(lazyLocal.noLazy) //
console.log(lazyLocal.lazy) // a little later than noLazy

console.log(lazyLocal.lazy) // never change again

lazyLocal.lazyNeverHappen = 1 // never invoke function
console.log(lazyLocal.lazyNeverHappen)

recommend example for refactor

You have some variables that cost a lot, and want to make them lazy without changing any logic.

As an example, require('typescript') call may cost a lot, as used here:

const ts=require('typescript') // expensive!!!
module.exports=()=>{
  console.log(ts)
  // a lot of ts here
}

Use lazy() to delay the require:

const lazy = require('@superjs/lazy')
const lazyLocal = lazy({
  ts:()=>require('typescript') // expensive!!!
})

You cannot make a local variable to be lazy, so it's a must: every ts be refactor to something.ts like lazyLocal.ts.

It's recommended to use [Refactor]/[Inline...] in IDE to automate this for you:

const lazy = require('@superjs/lazy')
const lazyLocal = lazy({
  ts:()=>require('typescript') // expensive!!!
})
const ts = lazyLocal.ts // [Refactor]/[Inline...] this

module.exports=()=>{
  console.log(ts)
  // a lot of ts here
}

You get perfectly what you want:

const lazy = require('@superjs/lazy')
const lazyLocal = lazy({
  ts:()=>require('typescript') // expensive!!!
})

module.exports=()=>{
  console.log(lazyLocal.ts)
  // a lot of lazyLocal.ts here
}

API

lazy(definitions)

  • returns: Object, return new object from definitions

convert function fields in definitions to lazy props, non-function stay the same. lazy({a:1, b:()=>1}) returns {a:1, b:lazyProp} with lazyProp being basically 1

lazy.define(obj, definitions)

  • returns: Object, return result object, return value is same as obj

same as lazy() but put props into existing obj.

Compatibility

You can use @superjs/lazy in both nodejs and browser environment.